Mathematics: How are these two equations related? (x^2-1)/(x+1)= x-1 and x^2-1=(x+1)(x-1)

How are these two equations related? (x^2-1)/(x+1)=

Ответ:

seddy86

07.01.2022

Mathematics

These two equations are related to each other by identity a^2-b^2=(a+b)(a-b)

Step-by-step explanation:

We have given equations

$\frac{x^2-1}{x+1}$

We know the algebraic identity

a^2-b^2=(a+b)(a-b)

So a^2-1^2=(x+1)(x-1)

So $\frac{x^2-1}{x+1}=\frac{(x+1)(x-1)}{x+1}=(x-1)$

So these two equations are related to each other by algebraic identity a^2-b^2=(a+b)(a-b)

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Ответ:

bri9263

17.07.2020

Mathematics

A= 150°

B=30°

C=150°

Step-by-step explanation:

Since a line is 180°, you can write an equation for C. C+30°=180° , from here use algebra to find C. The value of C will be 150°. When the value of C is 150° , since they're supplementary angles, the value of A will also be 150°.

Important thing to note:

The value of all these angles combined together is 360°.

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How are these two equations related? (x^2-1)/(x+1)= x-1 and x^2-1=(x+1)(x-1)

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