How do I do this problem (similar right triangles) please explain how you did it!!
ASAP!!!

by phythagoras theorem

(c+b)^2=(8)^2+(6)^2

(b+c)^2=64+36

(b+c)^2=100

b+c=√100

b+c=10.

by phythagoras theorem

(8)^2=(a)^2+(b)^2

64-b^2=a^2. {1}

by phythagoras theorem

(6)^2=(a)^2+(c)^2

36-c^2=a^2. {2}

In equation 1 and 2,

64-b^2=36-c^2

64-36= -c^2+b^2

28= b^2-c^2

28=(b+c)(b-c)

28=10(b-c)

b-c=28/10

b-c=2.8.

b+c=10

b-c=2.8

subtract both equations

c=3.6

option A is correct.

x=9 when y=21

Step-by-step explanation:

I used cross multiplication

7:3=21:x

7x=63

x=9