How do i factor 125x^3 -64 the answer is not (5x+4)(5x-4) or (5x-4)(25x^2 +15x+16)

The correct factorization would be (5x - 4)(25x^2 + 20x + 16).

The law of factoring cubes states that we use the following formula when we have two cubes being subtracted by one another.

(a - b)(a^2 + ab + b^2)

If we take the cube root of 125x^3 we get 5x, which will be our a value. If we take the cube root of 64, we get 4, which will be our b value. Then we plug in to the formula.

(5x - 4)((5x)^2 + (5x)(4) + 4^2)

(5x - 4)(25x^2 + 20x + 16)

I think the problem with your second answer is that you just did not properly multiply the 5x and the 4 to get 20x (instead you got 15x).

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