![enca2619](/avatars/14220.jpg)
enca2619
27.11.2019 •
Mathematics
How do i put this into my calculator?
Solved
Show answers
More tips
- W Work and Career Which types of activities are not subject to mandatory licensing?...
- C Computers and Internet Thin Client: What It Is and Why You Need It?...
- F Food and Cooking The Most Delicious and Simple Fish in Batter Recipe...
- F Food and Cooking Red Caviar: How to Choose the Best?...
- C Computers and Internet Clearing Cache: How to Speed Up Your Browser...
- S Style and Beauty How are artificial nails removed?...
- S Style and Beauty Secrets of Tying a Pareo: 5 Ways...
- F Food and Cooking Everything You Need to Know About Pasta...
Answers on questions: Mathematics
- M Mathematics In a school of 100 pupils , 30% study English, 2/5 study science and 150 study social studies, if the remaining study mathematis find the number of pupils who study mathematics...
- M Mathematics Living with parents: a pew research analysis stated that in 2012, 36% of the nation’s young adults ages 18-31—the so-called millennial generation—were living in their parents’ home....
- B Business Casey makes sure that he introduces himself to an it director of a company he has been interested in, even though the director is not familiar with casey’s profession of market research....
Ответ:
decimal form 9.77617459
Ответ:
6 +2√3 ft²
Step-by-step explanation:
Given a triangular pyramid with ...
an equilateral triangular baselateral edge length 2 ftlateral area 6 ft²Find
total surface areaSolution
Since corresponding edges are the same length, the area of each of the three faces is (6 ft²)/3 = 2 ft². This can be computed by ...
A = (1/2)s²·sin(α)
where s is the lateral edge length and α is the angle at the apex formed by the two edges that meet there. Filling in the given values, we find ...
2 ft² = (1/2)(2 ft)²·sin(α)
1 = sin(α) ⇒ α = 90°
That is, each face of the pyramid is an isosceles right triangle with legs of length 2 ft. The hypotenuse of that triangle, the base edge of the pyramid, is then 2√2 ft.
So, the base is an equilateral triangle with edge lengths 2√2 ft. Its area can be computed from ...
A = (√3)/4·s²
where s is the edge length of the equilateral triangle. That is, the base area is ...
A = (√3)/4·(2√2)² = 2√3 . . . . square feet
So, the total surface area of the pyramid is ...
(6 +2√3) ft² ≈ 9.4641 ft² . . . . . total surface area