Mathematics: How do I solve 1/3k-2k+4=10

How do I solve 1/3k-2k+4=10 - id1324105296348, deedee363

Ответ:

munozjosue258

20.01.2022

Mathematics

The value of k is -3.6

Solution:

Given that, we have to solve

$\frac{1}{3}k -2k + 4 = 10$

We have to find solution to given equation

From given,

$\frac{1}{3}k -2k + 4 = 10$

Make the denominators same in right side of equation

$\frac{1}{3}k - \frac{2k \times 3}{1 \times 3} + \frac{4 \times 3}{1 \times 3} = 10\\\\Simplify\\\\\frac{1}{3}k - \frac{6k}{3} + \frac{12}{3} = 10\\\\\frac{k-6k + 12}{3} = 10\\\\Isolate\ for\ k\\\\k - 6k + 12 = 10 \times 3\\\\Combine\ the\ like\ terms\\\\-5k + 12 = 30\\\\-5k = 30 - 12\\\\-5k = 18\\\\Divide\ both\ sides\ by\ -5\\\\k = -3.6$

Thus the value of k is -3.6

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Ответ:

jamesmith20

30.08.2021

Mathematics

Option (c) is correct.

Step-by-step explanation:

We are asked to find a cosine function has a period of 5, a maximum value of 20, and a minimum value of 0. Also the function is not a reflection of it's parent function over the x-axis.

We know that the period of is 2π.

To make a cosine function such that the period will be 5 we have to change the angle x to .

so, either of (a) or (c) option is correct.

As for a function f(x) it's reflection over the x-axis will be -f(x).

Hence (a) option does not hold true.

so we are left with only option (c)

Also we know that the range of lie between -1 to 1.

Hence the maximum value for function in option (c) will be 20( When ) and minimum value will be 0( when ).

Hence the resultant function is:

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How do I solve 1/3k-2k+4=10

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