Mathematics: How do you convert p(x) = -8x^2 - 64x to vertex form? I know the answer is p(x) = -8(x + 4)^2 + 128, but I m unaware of the steps taken to get to that stage. Any help is appreciated, thanks!

M=46Search Solve M/6-7=2/3The first thing that comes up has steps :]...

How do you convert p(x) = -8x^2 - 64x to vertex form?

fr996060

18.01.2022

p(x)=-8(x+4)^2+128

Step-by-step explanation:

Given, p(x)=-8x^2-64x

Take -8 factor common,

p(x)=-8(x^2+8x)

which can be written as

$p(x)=-8(x^2+2 \times 4x)$

Add and subtract by 16 inside bracket,

$p(x)=-8(x^2+2 \times 4x+16-16)$

$p(x)=-8((x^2+2 \times 4x+4^2)-16)$

p(x)=-8((x+4)^2-16)

$p(x)=-8(x+4)^2+8 \times 16$

p(x)=-8(x+4)^2+128

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