How do you expand 2(x-5)^2+3 to get general form

Y=2(x-5)^2+3  Y=2(x-5)(x-5)+3)  Foil method   Y=2(x(x-5)+5(x-5)+3)  Y=2(x^2-5x+5x+25)+3  Y=2(x^2-10x+25)+3  Y=2x^2-20x+50+3  Y=2x^2-20x+53

Nick gets 93 pounds

Step-by-step explanation:

June gets X

Nick gets 3X

Angad gets twice as much as Nick, so 2*(3X) = 6X

X+3X+6X=310

X= 31

We check

June gets 31 pounds

Nick gets 93 pounds

Angad gets 93x2 = 186 pounds

31+93+186 = 310. It's correct!