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06.05.2020 •
Mathematics
How do you get 2b+8 factored?
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Ответ:
Version one: equation is equal to 0
Given equation
2
b
+
8
that equals zero,
2
b
+
8
=
0
Isolate the 2b by subtracting 8 from each side
2
b
+
8
−
8
=
0
−
8
→
2
b
=
−
8
Divide both sides by 2 to isolate b
2
b
2
=
−
8
2
→
b
=
−
8
÷
2
=
−
4
Version two: no quantity equivalence
GIven function
2
b
+
8
we can apply the Distributive Property
convert to proper form
2
b
+
8
⇒
2
(
b
)
+
2
(
z
)
where
2
z
=
8
To get variable
z
⇒
8
÷
2
=
z
=
4
, therefore you have
2
(
b
)
+
2
(
4
)
or in factored form,
2
(
b
+
4
)
Step-by-step explanation:
Ответ:
2 (b + 4)
Step-by-step explanation:
First you rewrite 8 to be 4 times 2
2b + 2 * 4
Then you simply factor out the common term of 2
Ответ:
7 - (-11) would become 7 + 11, because the minus symbol would turn the negative into a positive. The answer is 7 + 11 = 18.