How do you graph y=-x-2?

Ok i'm going to try to explain this

Step-by-step explanation:

So the X Intercept is -2, and the Y intercept is -2 aswell.

Every 1x, it does down by one. Here is a graph.

a. t= (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂) ~

                Sa √(1/n₁ + 1/n₂)

b.  t_{50; 0.98} = 2.109[/tex]

c. There is sufficient evidence to warrant rejection of the claim that the two populations have the same mean and accept that the first population has a larger mean.

Step-by-step explanation:

Hello!

You have two random samples and it's believed that both samples have the same population mean. Symbolically: μ₁ = μ₂

a.

The statistic to use, to test the difference of population mean, assuming that both variables have a normal distribution and with unknown but equal population variances, is a pooled t.

t= (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂) ~

      Sa √(1/n₁ + 1/n₂)

b. If the hypothesis is that the mean of the first sample is greater than the mean of the second sample :

H₀: μ₁ = μ₂

H₁: μ₁ > μ₂

α: 0.02

The critical value is:

The rejection region is one-tailed. If the calculated value is equal or greater than 2.109, then you reject the null hypothesis. If the value is less than the critical value, then you do not reject the null hypothesis.

c.

t= (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂)   =      (14-9) - 0         = 4.49

      Sa √(1/n₁ + 1/n₂)                     4√(1/24 + 1/28)

Since the calculated value is greater than the critical value, then you reject the null hypothesis. In other words, the population mean of the first population is greater than the population mean of the second population.

I hope it helps!