How do you rewrite (x+7) square without parentheses

(x+7)(x+7) is the same as (x+7)^2
Using distributive property:
(x^2+7x+7x+49)
x^2+14x+49 is your answer.
A shorter way to do it if you know this:
If you know the general form ax^2+bx+c, to go from (x+7)^2 to that form is by knowing that b will be double 7, and that c will automatically be 7 squared.
Then, you know that it just goes to x^2+14x+49

x = 1

y = 0

Step-by-step explanation:

3x + 6y = 3

7x  + 3y = 7

=> 3y = 7 - 7x

=> y = -7/3x + 7/3

3x + 6(-7/3x + 7/3) = 3

=> 3x - 14x + 14 = 3

=> -11x = -11

=> -x = -11/11

=> -x = -1

=> x = 1

So, 3(1) + 6y = 3

=> 3 + 6y = 3

=> 6y = 0

=> y = 0/6

=> y = 0

So, x = 1

      y = 0