How do you round 1,534 so there is only one non zero digit

So there are 12 total outcomes.

a)

There are 4 5's on spinner.
P(5) = (total outcomes of 5) / (total outcomes) = 4 / 12 = 1/3.

b)

There are 1 1's, 3 3's, and 4 5's, so there are 1+3+4 = 8 odd outcomes

So P(odd #) = 8 / 12 = 2/3

c)

We already counted odd #. That's 8. There are 2 2's, so there are 10 "2 or odd #" outcomes

So that's P(2 or odd #) = 10 / 12 = 5/6

Hope this helps.