How do you solve this equation 27s-29=54s-83

s=2

Step-by-step explanation:

27s-29=54s-83

you want to get each variable on each side, so s on one side of the equal sign and the no variable on the other, but you can just put them there you can to add and subtract a variable of each side of them to get 0.

step 1.) 27s(-54s)-29=54s(-54s)-83

now you have -27s-29=-83, that's half of the equation done

step 2.) -27s-29(+29)=-83(+29)

you addition on this one because the even though it is a subtraction problem a - is always a negative number (think of it as adding a negative number)

you now have -27s=-54

step 3.) -27s/-27=-54/-27

at the end you (usually) always want the variable to be by itself so in this case s and on the left side. the answer is s=2

check.) you can check problems like this by substituting the variable for the number, so here is the check;

27x2-29=54x2-83

54-29=108-83

25=25

25 is the same as 25 which means that 2 is the correct answer

OK first change 3 3/4 to an improper fraction and that will give you  15/4. so you got that part right.  Next, change the division sign to multiplication. then flip the 1/2 to 2/1.  Then multiply 15 times 2 and that will give you 30. Then multiply 4 times 1 and that will give you 4. then you will have an answer of  30/4. Finally, since you a have a big number over a small number you divide 30 by 4 and that will give you 7 1/2. So it turns out that your little cheat sheet is wrong because when you check your answer you should go on Math-way to check it. Also, a little background about me is that I am in 8th grade and I am taking algebra 1 too.