Mathematics: How do you solve this problem: every month,$35 is withdrawn from hugo’s savings account to pay for gym membership. he has enough savings to withdraw no more than $315. for how many months can hugo pay for his gym membership? write an inequality and solve.

Third optionStep-by-step explanation:...

How do you solve this problem: every month,$35

Ответ:

smusisca53

24.05.2020

Mathematics

He can pay for the membership for 9 months.

Step-by-step explanation:

Divide 315 by 35, and then you get your answer.

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Ответ:

kaleec

06.09.2021

Mathematics

Third option

$\log _{10}\left(20x^5\right)-1\\$

Step-by-step explanation:

$5\log _{10}\left(x\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)\\\\5\log _{10}\left(x\right)=\log _{10}\left(x^5\right)\\\\=\log _{10}\left(x^5\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)\\\\\log _{10}\left(x^5\right)+\log _{10}\left(20\right)=\log _{10}\left(20x^5\right)\\\\$

$=\log _{10}\left(x^5\cdot \:20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\\=\log _{10}\left(20x^5\right)-1$

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How do you solve this problem: every month,$35 is withdrawn from hugo’s savings account to pay for gym membership. he has enough savings to withdraw no more than $315. for how many months can hugo pay for his gym membership? write an inequality and solve.

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