brillamontijo
09.04.2021 •
Mathematics
How do you solve x to the second power minus 7x plus 10 over 3x squared minus 9x to the second power
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Ответ:
4
Step-by-step explanation:
You can plug in the b's and see. You can also try to use a co-function identity and get a value for b that way.
Let's try the co-function identity:
sin(x)=cos(90-x).
First step:
cos(11b+2)=cos(90-[12b-4])
So one set of solutions can be found by solving:
11b+2=90-[12b-4]
Distribute:
11b+2=90-12b+4
Add 12b on both sides
23b+2=90+4
Simplify:
23b+2=94
Subtract 2 on both sides:
23b =94-2
23b =92
Divide both sides by 23:
b= 92/23
b= 4
So 4 is one value that will work.