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aeress
28.07.2019 •
Mathematics
How does the mean absolute deviation (mad) of the data in set 1 compare to the mean absolute deviation of the data in set 2? set 1: 82, 80, 90 set 2: 82, 80, 60, 90 the mad of set 1 is 6 less than the mad of set 2. the mad of set 1 is 5 less than the mad of set 2. the mad of set 1 is 5 more than the mad of set 2. the mad of set 1 is 6 more than the mad of set 2.
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Ответ:
n=3
Mean=(82+80+90)/3=252/3→Mean=84
Absolute Value: AV
MAD=[AV(82-84)+AV(80-84)+AV(90-84)]/3
MAD=[AV(-2)+AV(-4)+AV(6)]/3
MAD=(2+4+6)/3
MAD=12/3
MAD=4
Set 2: 82, 80, 60, 90
n=4
Mean=(82+80+60+90)/4=312/4→Mean=78
Absolute Value: AV
MAD=[AV(82-78)+AV(80-78)+AV(60-78)+AV(90-78)]/4
MAD=[AV(4)+AV(2)+AV(-18)+AV(12)]/4
MAD=(4+2+18+12)/4
MAD=36/4
MAD=9
MAD of set 2 - MAD of set 1 = 9-4=5
Second option: The MAD of set 1 is 5 less than the MAD of set 2.
Ответ:
The MAD of set 1 is 5 less than the MAD of set 2.
took the test
Ответ:
We conclude that will rent be at the end of this year 937.125$.
Step-by-step explanation:
We know that we have budgeted $850 per month for rent. Your landlord has just informed you that your rent is being raised by 5% now and another 5% on December 1st.
We calculate
now, we get
We conclude that will rent be at the end of this year 937.125$.