keigleyhannah30
05.07.2019 •
Mathematics
How many gallons of a 80% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 70% antifreeze?
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Ответ:
(x)(80%) + (60)(30%) = (x+60)((70%)
0.8x + 18 = 0.7x +42
0.8x - 0.7x = 42-18
0.1x = 24
and x = 240 Gal.
Ответ:
Answer with explanation:
The given Logarithmic equality is which can be solved as follows:
Used following properties of Log
but, if you substitute x= -6,in the given equation, that is
LHS≠RHS
So, x=6,is only solution of given logarithmic equality
∵
LHS=RHS