Mathematics: How many pieces 3 and three fifths in. long can be cut from 28 metal rods each 15 in. long? disregard waste.

How many pieces 3 and three fifths in. long can

ninjaerik4

10.03.2022

112 pieces

Step-by-step explanation:

1. Rewrite $3^{\frac{3}{5}}$ as a decimal. Divide the numerator and the denominator of the fractional part and add it to the integer part:

3+0.6=3.6in

2. You know that each metal rod is 15 inches long. Then, you must divide the lenght of each one by 3.6:

$pieces=\frac{15in}{3.6in}4.16$

3. The waste is 0.16, therefore, you obtain 4 pieces from a metal rod. The total pieces obtained from 28 metal rods are:

total=4pieces*28=112pieces

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drippyc1363

10.03.2022

116 whole pieces

Step-by-step explanation:

We have a 28 metal rods that are 15 inches long each, out of which we need to cut $3\frac{3}{5}$ inches long metal rods.

Firstly, we will convert the mix fraction into improper fraction and then divide the total length of the rod by it.

$3\frac{3}{5}$ inches = $\frac{18}{5}$ inches

Dividing the total length of rod by this length and multiplying it by 28 to get:

$\frac{15}{\frac{18}{5} }$ = $28 (15 * \frac{5}{18})$ = 116.6

Therefore, 116 whole pieces can be cut from the given length of rod.

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LilDicky

22.03.2023

im pretty sure its d

Step-by-step explanation:

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