How many quarts of water should be mixed with how many quarts of a 30% vinegar solution to obtain 12 qt of a 25% vinegar solution? hint: water is 0% vinegar.

Given that total volume of the solution = 12 quarts

Let volume of water added = x quarts

Then volume of 30% vinegar = (12-x) quarts

Given that x quarts of 0% water is mixed with (12-x)quarts of 30% vinegar to obtain 12 quarts of 25% solution

So we can write equation as:

[0% of x] + [30% of (12-x)] = [25% of 12]

or 0x + 0.30(12-x) = 0.25*12

or 0 + 3.6-0.30x = 3

or -0.30x = 3-3.6

or -0.30x = -0.6

x=2

Hence answer will be 2 quarts of water.

x=12 Proportion should be 1 2/3

Step-by-step explanation:

To find PT, subtract 26 from 65= 39

26/39 is equal to 2/3, so 30/(4x-3) should also be equal to 2/3

30/(4x-3)=2/3 (Cross Multiply)

30*3=90

2(4x-3)=8x-6

8x-6=90 (Add 6 to both sides)

8x=96 (Divide 8 from both sides)

x=12

QT is equal to 4(12)-3=45

RT is 75

Proportion: 65/39=1 2/3

75/45=1 2/3