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cheating53
13.10.2019 •
Mathematics
The perimeter of a rectangular field is 340 yd. the length is 70 yd longer than the width. find the dimensions.
the smaller side is?
the larger side is?
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Ответ:
170 = 70 + 2x
100 = 2x
50 = x
x+ 70 = 120
The smaller side is 50 yd
The larger side is 120 yd
Ответ:
Answer with Step-by-step explanation:
Let the width of rectangle be x
The length is 70 yd longer than the width.
i.e. Length= 70+x
The perimeter of a rectangular field is 340 yd.
We know that perimeter of rectangle= 2(Length+Width)
340= 2(70+x+x)
Dividing both sides by 2, we get
170= 70+x+x
i.e. 170= 70+2x
Subtracting both sides by 70, we get
100=2x
or 2x=100
Dividing both sides by 2, we get
x=50
Hence, Width of rectangle= 50 yd
Length= 70+50 yd
= 120 yd
Hence, smaller side is width of rectangle= 50 yd
and larger side is length of rectangle= 120 yd
Ответ:
for your mathematician brain