trvptierra
16.07.2019 •
Mathematics
How many solutions are there to the equation x1 +x2 +x3 +x4 +x5 = 18, where x1, x2, x3, x4, x5 are non-negative integers, given the follow restrictions: four of the variables must be odd, and the remaining variable (which may be odd or even) yield a remainder of 2 when divided by 3? justify your answer.
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Ответ:
4/3 is more than 1