How many values of θ will satisfy tan-1 0 = θ when 0º< θ< 90º?

We want to satisfy
tan⁻¹ 0 = θ when 0° < θ < 90°.

The restriction on θ places the angle in the 1st quadrant.
When tan θ = 0, θ = 0°, 180°, 360°, ...
If θ >= 0, then a solution exists in the 1st quadrant.
Because of the requirement θ>0, no answer satisfies the given equation.

None

x < 2

Step-by-step explanation:

12 - 5x > 8 - 3x

Now, add 5x on both sides

12 - 5x + 5x > 8 - 3x + 5x

12 > 8 + 2x

Now, subtracting by 8 on both sides

12 - 8 > 8 - 8 + 2x

4 > 2x

Now, dividing by 2 on both sides

4/2 > 2x/2

2 > x, which is same as x < 2.