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jalexus
11.10.2019 •
Mathematics
How to find dy/dx of the function y=x^(1/x) using logs and implicit differentiation?
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Ответ:
Taking logs:-
ln y = ln x^(1/x)
ln y = 1/x ln x
differentiating:-
dy/dx * 1/y = = 1/x * 1/x + lnx * - 1/x^2
dy/dx = (1/x^2 - lnx / x^2 ) * y
= [x ^(1/x) ( 1 - ln x) ]/ x^2 answer
Ответ: