Mathematics: How to solve for x 6x^2 + 7x +2 = 0

For this case we have that a quadratic equation is of the form:The roots are given by:We have the following equation:We look for the roots:We have to:So:We have two imaginary roots:...

How to solve for x 6x^2 + 7x +2 = 0 - id627205084380, CristianPaz

Ответ:

cherryy

18.01.2022

Mathematics

Explanation:

You need to factor this quadratic by playing with multipliers for 6 (1x6, 2x3, 3x2, 6x1) and multipliers for 2 (1x2, 2x1):

(

)

(

)

Now we can solve each term for

−

and

−

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Ответ:

wolfsaway

13.03.2023

Mathematics

For this case we have that a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

We have the following equation:

$4x ^ 2-3x + 9 = 2x + 1\\4x ^ 2-3x-2x + 9-1 = 0\\4x ^ 2-5x + 8 = 0$

We look for the roots:

$x = \frac {- (- 5) \pm \sqrt {(- 5) ^ 2-4 (4) (8)}} {2 (4)}\\x = \frac {5 \pm \sqrt {25-128}} {8}\\x = \frac {5 \pm \sqrt {-103}} {8}$

We have to:

i ^ 2 = -1

So:

$x = \frac {5 \pm \sqrt {103i ^ 2}} {8}\\x = \frac {5 \pm i \sqrt {103}} {8}$

We have two imaginary roots:

$x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}$

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How to solve for x 6x^2 + 7x +2 = 0

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