How to solve the integral of a square root function?

That is a very good question

Look Wade...

If you faced it in the form (x^2+a)^0.5 , you would use the substitution of x=a*tan(y)

If you faced it in the form (x^2-a)^0.5 , you would use the substitution of x=a*sec(y)

If you faced it in the form (a-x^2)^0.5 , you would use the substitution of x=a*sin(y) or even x=a*cos(y)

It would be better if you provided an example ...

I am with you if you faced any difficulties!

:)

0∙2=0

Step-by-step explanation:

Zero Property of multiplication is as follows :

The product of a number and 0 is equal to 0.

In option (c), 0 is multiplied by 2 and as a result, we get 0 as the answer.

It means,

0∙2=0

Hence, option (c) i.e. 0∙2=0 shows the Zero Property of Multiplication.