jkirby29
21.08.2019 •
Mathematics
How to solve this equation involving radicals.
8x(x – 6)1/2 + 4(x – 6)3/2 = 0
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Ответ:
8x(x) - 8x(6)1/2 + 4(x) - 4(6)3/2 = 0
8x² - 48x(1/2) + 4x - 24(3/2) = 0
8x² - 24x + 4x - 36 = 0
8x² - 20x - 36 = 0
x = -(-20) +/- √((-20²) - 4(8)(-36))
2(8)
x = 20 +/- √(400 + 1152)
16
x = 20 +/- √1552
16
x = 20 +/- √(16 × 97)
16
x = 20 +/- √16 √97
16
x = 20 +/- 4 √97
16
x = 20 +/- 4(9.848857802)
16
x = 20 +/- 39.39543121
16
x = 20 + 39.39543121 x = 20 - 39.39543121
16 16
x = 59.39543121 x = -19.39543121
16 16
x = 3.71221445 x = -1.212214451
Ответ:
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