Taylor1402
14.09.2020 •
Mathematics
How would I solve 16x^4-41x^2+25=0 ???
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Ответ:
First of all to make our equation simpler, we'll equal to a variable like 'a'.
So,
Now let's plug 's value (a) into the equation.
Now we turned our equation into a quadratic equation.
(The variable 'a' will have a solution set of two solutions, but 'x' , which is the variable of our first equation will have a solution set of four solutions since it is a quartic equation (fourth-degree equation) )
Let's solve for a.
The formula used to solve quadratic equations ;
The formula is used in an equation formed like this :
In our equation,
t=16 , b=-41 and c=25
Let's plug the values in the formula to solve.
So the solution set :
We found a's value.
Remember,
So after we found a's solution set, that means.
and
We'll also solve this equations to find x's solution set :)
So the values x has are :
, , and
Solution set :
I hope this was clear enough. If not please ask :)
Ответ:
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