How would I solve this?? Any help is much appreciated

155 km

Step-by-step explanation:

As shown:

At Δ BDC which is a right triangle at ∠D

BC = 78 km

m∠CBD = 90° - 64° = 26°

cos ∠CBD = BD/BC

∴ BD = BC * cos ∠CBD = 78 * cos 26° = 70.106 km

Port C is at a distace to the east of A = AO + BD

      = 85 + 70.106 = 155.106 km ≈ 155 km to the nearest km

No she would only be able to fit 729, because 9^2 equals 81, and 81*9 equals 729.