![esta54](/avatars/16436.jpg)
esta54
18.02.2021 •
Mathematics
How would i solve this? i have to find extraneous solutions along with it
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Ответ:
Step-by-step explanation:
Note that (m+2)(m+3) = m²+5m+6, so the least common denominator is
m²+5m+6.
Ответ:
The complete question is
find the slope of the tangent line and the equation of the tangent line at the given point,![x^2y-5xy^2](/tpl/images/0866/8987/d0b8c.png)
at the point (3,1).
Tangent = 1/23 , equation of tangent = 23y - x = 20
Step-by-step explanation:
We are given the equation
upon differentiation the given function we get
d (![x^2y-5xy^2](/tpl/images/0866/8987/d0b8c.png)
) /dt
=![2xy +x^2dy/dx - 5y^2 -10xy dy/dx =0](/tpl/images/0866/8987/8869e.png)
upon substituting x=3 ,y=1 we will get
dy/dx = 1/23
now the equation of the tangent will be
y-1 = 1/23 (x-3)
23 (y-1) = x- 3
23y - 23 = x -3
23y - x = 20