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twinkieslayer
18.12.2019 •
Mathematics
Huey and dunham (1987) measured the running speed of fence lizards, sceloporus merriam,in big bend national park in texas. individual lizards were captured and placed in a 2.3-meter raceway, where their running speeds were measured. lizards were then tagged and released. the data from the researchers is presented in modified form below. the lizard collections have occurred over three different years to see if the sprint speed of tagged lizards is changing over time.
sprint speed (m/s)
lizard
year one
year two
year three
1 1.43 1.37 1.60
2 1.56 1.30 1.71
3 1.64 1.36 1.83
4 2.13 1.54 1.92
5 1.96 1.82 1.09
6 1.89 1.79 2.06
7 1.72 1.72 1.86
8 1.80 1.80 1.78
9 1.87 1.87 2.04
10 1.61 1.88 2.13
the null hypothesis is that the mean of the lizard speed measurements are only different due to chance while the alternative hypothesis states that at least one year is different from the others.
[straight h subscript 0 : space straight mu subscript 1 equals space straight mu subscript 2 space equals space straight mu subscript 3 straight h subscript straight a : space at space least space one space straight mu subscript straight i space is space different space from space the space others]
calculate the anova table below.
source of variation sum of squares df mean squares f-ratio [f subscript 0.05 left parenthesis 1 right parenthesis comma d f subscript g r o u p s end subscript comma d f subscript e r r o r end subscript end subscript]
groups (treatments)
error
total
r2 =
do the anova results indicate that the null hypothesis (h0) can be rejected in favor of the alternative hypothesis (ha)? (yes or no)
answers should be rounded to the nearest three decimal places where appropriate
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Ответ:
x=-4, y=6
Step-by-step explanation: