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BreBreDoeCCx
26.01.2021 •
Mathematics
HURRYYY
For three consecutive years, Jack invested some money at the start of the year. The first year, he invested x dollars. The second year, he invested $1,000 less than times the amount he invested the first year. The third year, he invested $2,000 more than of the amount he invested the first year.
During the same three years, Samantha also invested some money at the start of every year. The first year, she invested $800 less than times the amount Jack invested the first year. The second year, she invested $1,200 less than 2 times the amount Jack invested the first year. The third year, she invested $1,600 more than of the amount Jack invested the first year.
If Jack and Samantha invested the same total amount at the end of three years, the amount Jack invested the first year is $ and the amount Samantha invested the last year is $ .
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Ответ:
Sam invested 38
57 over 38 minus 1,00
Ответ:
65
Step-by-step explanation:
Let c = number of correct answer.
Let i = number of incorrect answers.
There are 100 questions, so
c + i = 100
The correct answers are worth 0.5c.
The incorrect answers are worth -0.3i (a negative value because 30 cents is taken away for each incorrect answer)
The total worth of the answers is 0.5c - 0.3i. The total worth of the answers is $22.00, so the second equation is
0.5c - 0.3i = 22
We have a system of two equations in 2 unknowns:
c + i = 100
0.5c - 0.3i = 22
We'll use the substitution method to solve the system of equations.
Solve the firt equation for c:
c = 100 - i
Now substitute 100 - i for c in the second equation.
0.5(100 - i) - 0.3i = 22
50 - 0.5i - 0.3i = 22
-0.8i = -28
i = 35
c = 100 - i
c = 100 - 35
c = 65
65 problems were solved correctly.