I have 45 points... Charlie has a box with the following letters inside of it. What is the probability that he will draw a "D," put it back, and then draw an "A?" Write your answer as a simplified fraction.

3/7 and 2/7.

Step-by-step explanation:

P(e) = No of favourable outcomes/ Total no of possible outcomes.

total outcomes=3+1+1+2=7.

(1) p(D) = 3/7.

(2)p(A)=2/7

The probability of drawing a D does not affect the probability of drawing A so the events are independent so you just have to multiply the probabilities

There are 3 D out of 7
There are 2 A out of 7(because we put the card back)

3/7 * 2/7 =6/ 49

There are multiple answers:
• if he has 36 vases, he would be able to put one tulip in each. 
• if he has 18 vases, he would be able to put two tulips in each
• if he has 12 vases, he would be able to put three tulips in each 
• if he has 9 vases, he would be able to put four tulips in each
• if he has 6 vases, he would be able to put six tulips in each 
• if he has 4 vases, he would be able to put nine tulips in each 
• if he has 3 vases, he would be able to put twelve tulips in each
• if he has 2 vases, he would be able to put eighteen tulips in each