julianjacobg126
23.04.2020 •
Mathematics
I’ll give brainliest please help
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Ответ:
Given: A Right triangle ABC in which ∠B=90°,∠C=15°.A perpendicular from B to Hypotenuse AC is Drawn such that ∠ADB=∠BDC=90°
To Prove: BD=1/4×AC
Proof: In Δ ABC
∠A+∠B+∠C=180°[Angle sum property of triangle]
∠A+90°+15°=180°
∠A=180°-105°
∠A=75°
Similarly In ΔABD ,∠ABD=15° →∠A+∠ABD+∠ADB=180°
In Δ ABC
Sin 15°=(1)
In Right ΔADB,
Cos 15°=(2)
Sin 30°=2 Sin 15°× Cos 15° →Sin2A=2 SinA CosA
→ 1/2 = 2
Cancelling AB from numerator and denominator
→AC= 4 BD which is the result.