I’m not sure how to find Area.

B) 99

I see the eraser marks, thanks for actually giving it a try before asking

Step-by-step explanation:

split it into 3 parts

one is 4x12

the nest is 5x(12-5-4)

the last is 3x12

48

5x3=15

36

15+48+36

B) 99 square meters

Solution:
Area = (base)x(height)

1st method:
—pretend you are finding the area of a big parallelogram where height is given 12m. The base is 4m+5m+3m=12m
—Area=(base)x(height)=(12)(12)=144square meters
—Find the area of the small dimensions or rectangles;
area=(base)x(height)=(4)(5)=20square meters
area=(base)x(height)=(5)(5)=25square meters
—Subtract the area of small dimensions from the total dimension which is 144 square meters; 144-20-25= 99 square meters

2nd method:
—Split the two dimensional figures to three rectangles and determine the area of each rectangles;
area=(base)x(height)=(12)(4)=48square meters
area=(base)x(height)=(12)(3)=36square meters
12m-4m-5m=3m
area=(base)x(height)=(3)(5)=15 square meters
—Add up the areas of the three rectangles;
(48+36+15) = 99 square meters

Solution:

The two equation given which are in two variables are

1. y = x²-2 x -1 9

2. y + 4 x=5

Writing equation 2 as→y = 5 -4 x

Substituting the value of y in equation 1

⇒ 5 - 4 x = x² - 2 x - 19

⇒x² - 2 x + 4 x -19 -5=0

⇒ x² + 2 x -24=0

⇒x² + 6 x - 4 x - 24=0→→→[Breaking the middle term i.e term containing x]

⇒ x(x+6) -4(x+6)=0

⇒(x-4)(x+6)=0

⇒x-4=0 ∧ x+6=0

⇒x = 4     ∧    x= -6

Put x=4 in equation 2,

y + 4 ×4=5

y + 16=5

y = 5-16

y= -11

As one solution is (-6, 29), The other solution of the system of equation is (4, -11).