Mathematics: I’m not sure how to solve a problem like this and also state the excluded values. (4n/n+4)-(5n/n-3)

A for sure because it can be...

I’m not sure how to solve a problem like this

yasarhan2

21.01.2022

After solving, we get the final expression as: $\frac{-n^{2}-32n {} }{(n+4)(n-3)}$

Step-by-step explanation:

Given:

$\frac{4n}{n+4} - \frac{5n}{n-3}$

= $\frac{4n}{n+4} - \frac{5n}{n-3}$

Now taking L.C.M,

= $\frac{4n(n-3)-5n(n+4)}{(n+4)(n-3)}$

Simplify the equation in numerator,

= $\frac{4n^{2}-12n-5n^2 {-20n} }{(n+4)(n-3)}$

= = $\frac{-n^{2}-32n {} }{(n+4)(n-3)}$

Thus, this is the required solution: $\frac{-n^{2}-32n {} }{(n+4)(n-3)}$

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