Mathematics: I need help with this question !

I need help with this question ! - id14525628, abbbaayyyy1709

vanessagomezcx

06.10.2021

Solutions given:

$\frac{SinA}{SinB}=p$

SinA=pSin B or

Sin B=Sin A/p

$\frac{CosA}{CosB}=q$

Cos A=qCos B

Cos B=Cos A /q

now

TanA= $\frac{Sin A}{Cos A}=\frac{psinB}{qCosB}=\frac{p}{q}*TanB$

again

TanB= $\frac{Sin B}{Cos B}=\frac{Sin A /p}{CosA/q}=\frac{q}{p} Tan A$

now

$\frac{TanA}{TanB}=\frac{p}{q}$

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noneofurbznessp2yc11

06.10.2021

Refer to the attachment

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19mcgough

06.04.2020

What are the numbers so I can do the problem.

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