I need help writing this into an equation

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Ответ:

hamzaha

01.07.2022

Mathematics

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121 . We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}$

$x=\frac{-224\pm\sqrt{50176+7744}}{-32}$

$x=\frac{-224\pm\sqrt{57920}}{-32}$

$x=\frac{-224\pm240.66574}{-32}$

$x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}$

$x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}$

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

$x\approx -0.52, x\approx 14.52$

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

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