jaejaeJae941

17.12.2020 •

Mathematics

I need helppppppp pleaseeee

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Ответ:

jhart3257

26.02.2022

Mathematics

we have

f(z)=z^2-2+2i

remember that

$i^{2}=-1$

Step 1

Find the first output value for z=0

substitute in the fractal-generating function

f(0)=0^2-2+2i

f(0)=-2+2i

Step 2

Find the second output value for z=-2+2i

substitute in the fractal-generating function

f(-2+2i)=(-2+2i)^2-2+2i

= 4-8i+4i^2-2+2i

$=2-6i+4*(-1)\\= 2-6i-4\\=-2-6i$

f(-2+2i)=-2-6i

Step 3

Find the third output value for z=-2-6i

substitute in the fractal-generating function

f(-2-6i)=(-2-6i)^2-2+2i

=4+24i+36i^2-2+2i

$= 2+26i+36*(-1)\\= 2+26i-36\\=-34+26i$

f(-2-6i)=-34+26i

therefore

the answer is

the first three output values of the fractal-generating function are

[-2+2i,-2-6i,-34+26i]

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