I wasn't present while they taught this, can someone help me understand how to do this type of work? and help me solve if possible.

I wasn't present while they taught this, can someone help me understand how to do this type of work

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Ответ:

cgarnett5408

17.05.2021

Mathematics

$\text{cos}(M)=\frac{19}{20}$

Step-by-step explanation:

Please find the attachment.

We have been given that in right triangle LMN, L and M are complementary angles and $\text{sin}(L)=\frac{19}{20}$ . We are asked to find the $\text{cos}(M)$ .

We know that sine relates opposite side of right triangle to hypotenuse.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

We also know that cosine relates adjacent side of right triangle to hypotenuse.

$\text{cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}$

We can see from the attachment that LM is hypotenuse and MN is adjacent side of our given triangle.

$\text{cos}(M)=\frac{19}{20}$

Therefore, $\text{cos}(M)$ is $\frac{19}{20}$ as well.

In right traingle lmn, l and m are complementary angles and sin(l) 19/20 is . what is cos(m)?

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