I WILL GIVE BRAINLIEST Use the slope formula to find the slope of the line passing through the points (−5,4) and (5,0). Use pencil and paper. Find two more points that the line passes through.
The slope of the line is nothing. ​(Type an integer or a simplified​ fraction.)

Slope = -2/5 new points (5/2,1) and (5,0)

Step-by-step explanation:

Standard point slope equation:

y = mx + b   where m is the slope and b is the y-intercept.

First find the slope between the given points.

Slope = rise/run

m = (y1 - y2) / (x1 - x2)

   = (4 - 0)/(-5 - 5)

   = 4/-10 = -2/5 then

y = (-2/5)x + b then one point (I picked (-5,4) to find b

4 = (-2/5)(-5) + b

4 = 2 + b

b = 2

y = (-2/5)x + 2 then pick an x and find y for additional points.

x = 5/2

y = (-2/5)(5/2) + 2

y = -1 + 2

y = 1 so the point is (5/2,1) and let x = 5

y = (-2/5)(5) + 2

y = -2 + 2

y = 0 so the point is (5,0)

Suppose that :

A = ( 5 , 0 )

B = ( - 5 , 4 )

Then we have :

Slope = [ y(B) - y(A) ] ÷ [ x(B) - x(A) ]

Slope = [ 4 - 0 ] ÷ [ -5 - 5 ]

Slope = 4 ÷ ( - 10 )

Slope = - 4/10

Slope = - 2/5

It's time to find the formula of this linear function using following formula :

y - y ( A or B ) = Slope × ( x - x ( A or B ) )

I'm gonna using point A but u can do it with point B which will gave the same answer :

y - 0 = - 2/5 × ( x - 5 )

y = - 2/5 x + 2

We have the formula of the function now thus it's time to find two more points that line passe through ;

To do that we just have to put two desired values of x instead of it and find the y to have the coordinate of those points that line passes through :

I'm gonna use x = - 10 and x = 15 :

x = - 10x = 15

y = - 2/5 × ( -10 ) + 2 y = -2/5 × ( 15 ) + 2

y = 4 + 2 y = - 6 + 2

y = 6 y = - 4

Thus ( -10 , 6 ) & ( 15 , - 4 ) are two other points that line passes through.