Mathematics: Ice is placed around a bowl of water to lower the temperature. the equation d=−7/5t+22 shows the time, t, measured in minutes and temperature, d, measured in degrees celsius. which statement is correct? a)the temperature of the water decreases 5°c every 7 minutes. b)the temperature of the water increases 7°c every 5 minutes. c)the temperature of the ice that is around the bowl is 22°c d)before cooling begins, the temperature of the water is 22°c

Explanation:i need to know what this is about so i can do it...

Ice is placed around a bowl of water to lower the

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13.03.2022

d)Before cooling begins, the temperature of the water is 22°C

Step-by-step explanation:

Given equation that shows the temperature of the bowl after t minutes,

$D=-\frac{7}{5}t+22$

Initially ( when ice is not placed ) t = 0,

So, the temperature of the water,

$D=(0) + 22 = 22^{\circ}$

i.e. Option d) is correct.

If t = 7 minutes,

The temperature would be,

$D=-\frac{7}{5}\times 7+22$

$=-\frac{49}{5}+22$

$=-\frac{49+110}{5}$

$=\frac{61}{5}$

$=12.2^{\circ}C$

So, the change in temperature = 12.2° - 22° = -9.8°,

Thus, option a) is incorrect.

If x = 5 minutes,

The temperature would be,

$D=-\frac{7}{5}\times 5+22=-7+22 = 15^{\circ}$

Change in temperature = 15° - 22° = -7°,

So, Option b) is incorrect.

∵ The temperature of the ice must be less than 22°,

Thus, option c) is incorrect.

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