cam3227
27.01.2020 •
Mathematics
Identify an equation in point-slope intercept form for the line perpendicular to y=3x+5 that passes through (4,-1)
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Ответ:
y + 1 = - (x - 4)
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x + 5 is in this form
with slope m = 3
Given a line with slope m then the slope of a line perpendicular to it is
= - = -
The equation of a line in point slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
here (a, b) = (4, - 1), thus
y - (- 1) = - (x - 4), that is
y + 1 = - (x - 4) ← in point- slope form
Ответ:
2) You are correct.
3) : 3 × 3 × 3 × 3 × 3 × 3 × 3 = 2187
4) : 10 × 10 × 10 × 10 × 10 × 10 = 100000
5) 20 = × 5
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