Mathematics: Idon’t understand why is it “not possible”. -2/3x 4 and 3/4x -6 and also i don’t understand why is it “all real numbers”. 3x-9≤9 or 4-x≤3

D. 4Step-by-step explanation:∆VWZ ~ ∆VXY, therefore:VW = 8VX = 8 + WXVZ = 18VY = 27Plug in the values Cross multiplySubtract 144 from each sideDivide both sides by 18WX = 4...

Idon’t understand why is it “not possible”. -2/3x

Ответ:

kittimau

10.03.2022

Mathematics

Let's solve the inequalities: we have

$-\dfrac{2}{3}x$

and

$\dfrac{3}{4}x$

Since the two inequality must be true at the same time (there is an "and" between the two), we should find a number that is, at the same time, greater than -6, and smaller than -8. But since -6 is greater than -8, a number greater than -6 is automatically greater than -8 as well. So, it is impossible for a number to be greater than -6 and smaller than -8.

If negative numbers confuse you, this example shows the same (impossible) logic: we can't ask for a number to be greater than 10, but smaller than 3.

As for the second exercise:

$3x-9\leq 9 \iff 3x \leq 18 \iff x \leq 6$

$4-x\leq 3 \iff -x \leq -1 \iff x \geq 1$

So, a number satisfies this system if it is smaller than 6 or greater than 1. This means that at least one of the conditions must be satisfied, and this is always the case:

If we choose a number smaller than 1, the second condition is metIf we choose a number between 1 and 6, both are metIf we choose a number greater than 6, the first condition is met

So, whatever number we choose, at least one of the conditions will be true, and the logical "OR" will be satisfied.