Mathematics: If 2x^2-5x+7 is subtracted from x^2+2x-11, what is the leading coefficient? a)-18 b)2 c)-2 d)7

If 2x^2-5x+7 is subtracted from x^2+2x-11, what - id2257221111598425, kajjumiaialome

huntertaleiya

01.04.2021

-1

Step-by-step explanation:

2x² - 5x + 7 is subtracted from x² + 2x - 11, so

(x² + 2x - 11) - (2x² - 5x + 7)

x² + 2x - 11 - 2x² + 5x -7 (Distribute the negative)

-x² + 7x - 18 (Combine like terms)

The leading coefficient is the coefficient of the first term, so it is -1.

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kyliemorgan8623

30.04.2023

We know that :

$\sf{\bigstar \ \ Cos\theta = \dfrac{Adjacent \ Side}{Hypotenuse}}$

From the figure, We can notice that :

Ф Adjacent side length = 8

Ф Hypotenuse length = 11

$\sf{\implies Cosx^{\circ} = \dfrac{8}{11}}$

$\sf{\implies x^{\circ} = Cos^{-1}\bigg(\dfrac{8}{11}\bigg)}$

$\sf{\implies x^{\circ} = 43.34}$

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