If 37 exceeds three times the sum of a number and 5 by 1, what is the number?

okay i’m not exactly certain but i can try to help. try setting the two equations equal to each other. since they are on the same side they are probably congruent. again, not certain

Step-by-step explanation:

9x + 11= 10x+5

move 10x to the right side and change it’s sign:

-10x + 9x + 11= 5

that leave you with -1x

-1x+11=5

-1x + 11-11 =5-11

-1x=-6

divide -1 by both sides, leaving you with

x=6

again, not sure but this is what i would try first. if this doesn’t work, try to set them equal to 180.