Kelseygrace8372
03.02.2020 •
Mathematics
If 3a+4b = 4a-4b = 21 find the value of a
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Ответ:
4a-4b=21
4a=21+4b
a=(21+4b)/4
now using 1st and 2nd
3(21+4b)/4+4b=4(21+4b)/4-4b
(63+12b+16b)/4=(84+16b-16b)/4
63+28b=84
28b=21
b=21/28
b=3/4
now using 4a-4b=21 we have
4a-4(3/4)=21
4a=3=21
4a=24
a=6
Ответ:
negative two and the infinite symbol