limelight11
03.04.2021 •
Mathematics
if (5a-1) is divided by b, the result is 3 and the remainder is 4. If (b+8) is divided by a, the result is 3 and the remainder is 1/4a (¼a). Form two equations in a and b. Solve for a and b.
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Ответ:
a = 4
b = 5
Step-by-step explanation:
We should understand that the product of the result of a division (quotient) and the number divided (divisor) plus the remainder, will give the number we are dividing (dividend)
From the first equation;
5a - 1 = 3(b) + 4
5a - 1 = 3b + 4
5a - 3b = 4 + 1
5a - 3b = 5 •••••(i)
Secondly;
b + 8 = 3(a) + a/4
Multiply through by 4
4b + 32 = 12a + a
4b + 32 = 13a
4b - 13a = -32 ••••••••(ii)
Multiply equation i by 4 and ii by 3
20a -12b = 20
12b -39a = -96
Add both equations
20a-39a = 20-96
-19a = -76
a = 76/19
a = 4
Recall;
5a-3b = 5
5(4) - 3b = 5
20 - 3b = 5
20-5 = 3b
3b = 15
b = 15/3
b = 5
Ответ:
-10x-9
4cos2 (x)-1=0
+2=3
CAN I HAVE BRAINLIEST SINCE I ANSWERED CORRECT