If a CONE has a DIAMETER of 10 centimeters and a Volume of 225 cubic centimeters, what is its approximate HEIGHT

The approximate height is 8.9 cm

Step-by-step explanation:

To find the height of a cone with a diameter of 10 cm and a volume of 225 cubic centimeter, we will follow the steps below;

first, write down the formula for finding the volume of a cone

v=πr²

where v is the volume of the cone

r is the radius and h is the height of the cone

from the question given,

diameter = 10 cm   but       d=2r       this implies  that    r=     r=   10/2   =    5cm

hence   r= 5cm

Also    v= 225 cm³

π  is a constant and is ≈ 3.14

We can now proceed to insert the values into formula and then solve for h

v=πr²

225 ≈ 3.14 × 5² ×

225 ≈ 78.5 ×

225 ≈

cross-multiply

675 = 75.8 h

divide both-side of the equation by 75.8

8.9 ≈ h

h≈ 8.9

Therefore, the approximate height is 8.9 cm

Step-by-step explanation:

A) QSP  and RSP are simular

B) Because the line PS is at a right angle to  QR.. angle S for each triangle is the same.. and since  the angle for P for each triangle is also the same so... angle Q and R have to be the same ... so they are the same/ similar triangles

C)  .. they have to have the same proportions as each other sooo..

so one triangle is 3x the size of the other..  but.. for some odd reason they are not asking about the bigger triangle..so we don't need to know that RQ=16... they want to know the hypotenuse of the given triangle with 4 on one of the legs.. soooo = 5.6568....