If a crane applied 360n of force to a railroad car that weighed 60 kg, how fast could it accelerate?

Step-by-step explanation:

Force F = mass m × acceleration a

F = 360N, m = 60kg

: 360 = 60 × a

a = 360/60

a = 6m/s^2

w = x and ΔABC ~ ΔFED

Step-by-step explanation:

we know that

In a right triangle

If sin(A)=cos(B)

then

Angles A and B are complementary

so

A+B=90°

In this problem

If sin(y°) = cos(x°)

then

Angles y and x are complementary

so

x+y=90°

therefore

In the triangle FED

w+y=90° > by complementary angles

In the triangle ABC

z+x=90° > by complementary angles

so

w=x and z=y

Remember that

If two triangles are similar, then the corresponding angles are congruent

In this problem

The corresponding angles of triangles ABC and FED are congruent

therefore

ΔABC ~ ΔFED