Mathematics: If a polynomial function f(x) has roots 3 and square root of 7 what must also be a root of f(x)? a negative square root of 7 b i square root of seven c –3 d 3i

If a polynomial function f(x) has roots 3 and

Ответ:

lindseylewis313

07.01.2022

Whenever you have a root of sqrt #, you must have the matching - (or positive).
This is because when you take a square root you get two solutions a positive and a negative.
The answer is LETTER A

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Ответ:

glowbaby123

07.01.2022

Mathematics

$-\sqrt{7}$

A is correct.

Step-by-step explanation:

A polynomial function f(x) has root $3\text{ and }\sqrt{7}$ .

3 is a real number.

$\sqrt{7}$ is an irrational number.

The zeros or root of the function always occurs in conjugate pair.

Conjugate pair: A root has two form one positive and one negative.

e.g: $a+\sqrt{b},a-\sqrt{b}$

For the given function f(x), $\sqrt{7}$ should be in conjugate pair.

One more possible root would be $-\sqrt{7}$

Hence, the one root must be negative of root of 7

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Ответ:

emilypzamora11

15.08.2020

Mathematics

Would assume:

f(n + 1) = f(n) - 2

f(2) = f(1 + 1) = f(1) - 2 = 18 - 2 = 16

f(3) = f(2 + 1) = f(2) - 2 = 16 - 2 = 14

f(4) = f(3 + 1) = f(3) - 2 = 14 - 2 = 12

f(5) = f(4 + 1) = f(4) - 2 = 12 - 2 = 10

f(5) = 10

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If a polynomial function f(x) has roots 3 and square root of 7 what must also be a root of f(x)?
a negative square root of 7
b i square root of seven
c –3
d 3i

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