mallorywoods8
08.07.2021 •
Mathematics
If a silver alloy that costs $6.75 an ounce is
going to be mixed with 55 ounces of a silver
alloy that costs $10 an ounce to make a
mixture that costs $8 an ounce, how many
ounces of the $6.75 an ounce alloy must be
used?
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Ответ:
9514 1404 393
88 ounces
Step-by-step explanation:
Let x represent the number of ounces of the less expensive alloy in the mix. Then the cost of the mix will be ...
6.75x +10(55) = 8(55+x)
110 = 1.25x . . . . . . subtract 440+6.75x
88 = x . . . . . . . . divide by 1.25
88 ounces of $6.75/oz silver must be used.
Ответ:
answer:the first one.rolling a of 7
Step-by-step explanation:bc the other ones cannot be corresct